Puzzles and Brain Teasers
Brain teasers and puzzles help you to train your brain. So go ahead, take our Brain Teaser. And don't take a peek at the answer until you have tried really hard.Brain Teasers and Puzzles
All cars do not have either steering wheel or horn or headlight
Exactly 19% of cars do not have just one of these
Atleast 67% of cars do not have steering wheels
Atleast 83% of cars do not have horns
Atleast 73% of cars do not have headlights
What percentage of cars do not have steering wheel, horn and headlight?

42% cars do not have steering wheel, horn and headlight.
Since figures are supplied in percentages, let us assume that there are 100 cars. Hence, there should be total 300 items i.e. 100 steering wheels, 100 horns and 100 headlights.
From the given data, we know that there is shortage of at least (67+83+73) 223 items in every 100 cars.
Also, exactly 19 cars do not have just one item. It means that remaining 81 cars should account for the shortage of remaining (223-19) 204 items.
If those remaining 81 cars do not have 2 items each, there would be a shortage of 162 items. But total of 204 items are short.
Hence, at least (204-162) 42 cars do not have all 3 items - steering wheel, horn and headlight.
- President
- Vice president
- Secretary
- Treasurer
- F wants to be President if E is Vice president.
- B does not want to be either President or Vice president.
- E does not work if both A and B work.
- D does not work if any of A and B works.
- C works only if F works along with B.

- F - President
- E - Vice president
- B - Secretary
- C - Treasurer
Let F be the President, and complying with his conditions, E the Vice President.
B does not wish to be either the President, Vice-President, so he is most likely to be the Secretary or Treasurer. Let him be the Secretary.
Besides it will not violate E's condition who would not work if both A and B work, but can work with either of them.
D cannot be appointed as Treasurer, with in the work force. Hence the last option is C, whose conditions are compatible with the elected work force.

It took 28 days for the toad to scale the well.
Until the 27th night the toad would have managed to scale a height of 27 yards, which can be obtained by simple calculation:
27(3-2) = 27
On the 28th day, he would cover 3 yards during the day, which accomplishes him the target. No need of calculating after that.
- Clark and Jones are neighbors and they drive each other to work.
- Jones earns more than mason.
- The police man earns more than the druggists and the grocer.
- The policeman does not have the druggist as a neighbor.
- The butcher walks to work.
- Policeman does not meet the grocer until he arrests him for committing an offence.
- Clark beats Smith every time they play football.
Find out who is who?

Consequently,
Smith - Policeman
Mason - Butcher
Clark - Druggist
Jones - Grocer
From the given statements it can be inferred that:
- Policeman and doctor are not neighbors, nor is the policeman a neighbor of the grocer.
- Butcher walks home alone. Therefore the doctor and grocer are neighbors for sure. Either of them is Clark or Jones.
- Jones earns more than mason. But both Clark and Jones are earning less than the policeman, hence Smith ought to be the policeman.
- The butcher walks home alone. Since he is neither Clark nor Jones, he is obviously mason.
- Lastly policeman is beaten by Clark at football and doesn't meet grocer.
- Hence Jones ought to be the grocer, while Clark the druggist.
On the first day A gave machines to B and C as many as they already had.
On the second day B gave as many machines to A and C as many as they possessed at that time.
On the final day, C did the same thing.
At the end of this transaction each one of them had 24. Find the number of machines each originally had.

A had 39 machines
B had 21 machines
C had 12
Let us assume, originally,
A had a machines
B had b machines
A had c machines
Hence as per the conditions, we have:
A | B | C | |
---|---|---|---|
At the beginning | a | b | c |
First Day | a-b-c | 2b | 2c |
Second Day | 2(a-b-c) | 2b-(a-b-c+2c) | 4c |
Third Day | 4(a-b-c)..(i) | 2{2b-(a-b-c+2c)} = 2(2b-a+b-c)..(ii) | 4c-{2b-(a-b-c+2c)+ 2(a-b-c)} = 4c-[a+b-3c]..(iii) |
At the end of the final transaction, each dealer has 24 machines, thus we can say,each of (i),(ii),(iii) adds upto 24.
4(a-b-c)=24
2(2b-a+b-c)=24
4c-[a+b-3c]=24
Solving the above equations, we get:
Can you tell the no. of bananas he originally had? Oh, by the way, he never had to cut a banana.

The boy originally had 7 bananas.
In order that the little boy should have disposed of all the bananas, he had remaining after his second sale, he must have had at least one whole banana remaining so that he could deduct from it 'half of his bananas plus ½ a banana', for the third and the final sale. Therefore if one banana represents what remained after the second sale then he must have sold two bananas in his second sale, from the three bananas left after the first sale. Lastly, if 3 bananas only represent half the original number, plus half a banana, then he must have started with [(3x2) + 1] or 7 bananas.
In a nutshell:
Total bananas originally possessed by boy =7
No. sold in first sale = 3½ + ½ = 4
No. remaining after first sale = 7-4 = 3
No. sold in second sale = 1½ + ½ = 2
No. remaining after first sale = 3-2 = 1
No. sold in last sale= ½ + ½ = 1
No. remaining after last sale = 1-1 = 0
Keyword: RELAX
- laze
- unlax
- recline
- unwind
- tranquilize
- repose

- laze
- unlax
- recline
- unwind
- tranquilize
- repose
- Cellphone
- Ipod
- Laptop
- Food warmer
- Coffee brewing machine

Food warmer is in the topmost rack and is the correct option.
If we go by these two pre-conditions - "Cellphone is in the rack right above the Ipod" and "Food warmer is in the rack right above the Cellphone", then in a sequence from top to bottom, we have:
- Food Warmer
- Cellphone
- Ipod
- Food Warmer
- Cellphone & Laptop
- Ipod
- Food Warmer
- Cellphone & Laptop
- Ipod & Headphones
- Food Warmer
- Cellphone & Laptop
- Ipod & Headphones
- Coffee Brewing Machine